The width of a rectangle is 5 units less than the length. If the area is 150 square units, then find the dimensions of the recta
ngle.
2 answers:
Answer:
The length is 15 and the width is 10
Step-by-step explanation:
Let l = length
w = l-5
We know the area is 150
A = l*w
150 = l ( l-5)
150 = l^2 - 5l
Subtract 150 from each side
0 = l^2 - 5l - 150
Factor
0= ( l+10) ( l-15)
Using the zero product property
l+10 =0 l-15=0
l = -10 l = 15
Since we cannot have a negative length
l = 15
w = 15-5 = 10
The length is 15 and the width is 10
let the length and width of the rectangle be L and w
given:
w = L-5
Area = 150 sq inches
area of the rectangle = L*w
150 = L*(L-5)
150 = L squared -5l
L squared - 150 = 0
L squared - 15L+10L -150 = 0
L(L-15)+10(L-15)= 0
(L+10)(L-15)=0
(L+10 )= 0 or (L-15) = 0
L = -10 is not possible as there wont be negative lengths
so L = 15
there fore w = L - 5 = 15 - 5 = 10
L = 15 in and w = 10 in
You might be interested in
-2x + xy = 30.....when y = 8
-2x + 8x = 30
6x = 30
x = 30/6
x = 5 <==
Answer:
h =2.6
Step-by-step explanation:
2.5/6
2.5+6
=
2.6
The answer is no solution, if my math is correct.
Answer: 5 8 7 9 5 6
Step-by-step explanation:
Because you go by which is closer to the denominator
Answer:
$145.50
Step-by-step explanation:
C = 45.50 + 2n
45.50 + 2X 100 = $145.50