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artcher [175]
2 years ago
9

True or False. One character in peas that Mendel studied was yellow versus green seeds.A cross between a homozygous yellow line

(YY) and a homozygous green line (yy) will result in F1 plants that are heterozygous (Yy) for this trait and produce yellow seeds.
Biology
1 answer:
Yakvenalex [24]2 years ago
5 0

Answer:

True

Explanation:

Gregor Mendel worked with pea plant (Pisium sativum) and one of the genes he closely observed was the one coding for seed colour.

He crossed a yellow seeded pea plant (YY) with a green seeded one (yy). These parent plants are referred to as PUREBRED PARENTS. He realized that the resulting offsprings called F1 generation were all Yellow seeded, which is in accordance with Mendel's law of dominance and uniformity (expression of a dominant allele in a gene)

A significant observation was that the F1 offsprings were genetically mixed or heterozygous i.e. their genotype consisted of two different alleles (Yy).

This concept explained that, in a gene, an allele is capable of masking the expression of another. The allele that masks or is expressed is the DOMINANT allele while the allele being masked is called RECESSIVE allele.

In this case, the yellow seeded pea plant is dominant over the green seeded pea plant (recessive).

Mendel provided proof that an allele can be present but masked when he crossed two heterozygous F1 plants to produce F2 offsprings (3 yellow, 1 green).

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3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
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Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
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1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

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Explanation:

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The elements that makes up ATP are:

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