1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5
2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18
Given Information:
Mean SAT score = μ = 1500
Standard deviation of SAT score = σ = 3
00
Required Information:
Minimum score in the top 10% of this test that qualifies for the scholarship = ?
Answer:

Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

Therefore, you need to score 1884 in order to qualify for the scholarship.
How to use z-table?
Step 1:
In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2
Step 2:
Then look up at the top of z-table and note down the value of the that column which is 0.08
Step 3:
Finally, note down the intersection of step 1 and step 2 which is 1.28
Given:
Population proportion,

= 57% = 0.57
Population standard deviation, σ = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%
The standard error is

The confidence interval is

where

= sample proportion
z* = 1.96 at the 95% confidence lvvel
The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)
Answer: Between 0.417 and 72.4), or between (41% and 72%)
Y^2+36, because you square y and 6