The prime numbers on the dice are 1,2,3,5 and 7 , the theoretical probability is
, which is 62.5%, the number of prime numbers in the outcome is 15, so the experimental probability is
, which is 75%, the difference between the experimental probability and the <span>theoretical probability is 12.5%.</span>
Since a(n)=-3(a(n-1)) the common ratio is -3, and a(1)=-3 so
a(n)=-3(-3^(n-1)) so the first four terms are:
-3, 9, -27, 81
69×2 [8+12-10×2+ (7-5) -1] -6
69×2 [8+12-10×2+2-1] -6
69×2 [8+12-20+2-1] -6
69×2 [20-20+2-1] -6
69×2 [0+2-1] -6
69×2 [1] -6]
138 [1] -6
138-6
132
I believe this is ur answer.
Answer:
a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between 0.6290 and 0.6948.
b. If the sample size is changed, the confidence interval changes as the standard error depends on sample size.
About 90% percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 10% percent will not contain the true population proportion.
Step-by-step explanation:
We have to calculate a 90% confidence interval for the proportion.
The sample proportion is p=0.6619.
The standard error of the proportion is:
The critical z-value for a 90% confidence interval is z=1.6449.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 90% confidence interval for the population proportion is (0.6290, 0.6948).
Answer:
98% probability that at least one of Harold and Maude will make it to the cruise
Step-by-step explanation:
Independent probabilities:
When two events are independent, the probability of the two events happening simultaneously is the multiplication of each probability.
Probability that none makes it to the cruise:
Harold's flight has an 80% chance of making it, so 100 - 80 = 20% probability of missing.
Maude's flight has a 90% chance of making it on time, so 100 - 90 = 10% probability of missing.
Both missing: 0.2*0.1 = 0.02.
2% probability of both missing.
Probability that at least one makes it to the cruise:
Either both miss, or at least one makes it. The sum of the probabilities of these events is 100%. So
2 + p = 100
p = 98%
98% probability that at least one of Harold and Maude will make it to the cruise
