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Lena [83]
3 years ago
5

How many seconds in an 8 hour work day

Mathematics
2 answers:
aliina [53]3 years ago
8 0
1 hour=3600 seconds
8 times 3600 =28800
vlabodo [156]3 years ago
5 0
The answer would be
28,800 seconds
You might be interested in
1. -3 2/5 + b = 8 1/5<br><br><br>2. -7/3 n = -42<br><br>PLZ HELP ASAP I WILL MARK BRAINLIEST
diamong [38]
1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5

2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18
7 0
3 years ago
The SAT Reasoning Test (formerly called the Scholastic Aptitude Test) is perhaps the most widely used standardized test for coll
mihalych1998 [28]

Given Information:  

Mean SAT score = μ = 1500

Standard deviation of SAT score = σ = 3 00

Required Information:  

Minimum score in the top 10% of this test that qualifies for the scholarship = ?

Answer:

\bar{x} = 1884\\

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.  

We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

P(X > \bar{x} )= P(Z > \bar{x}) = 0.10\\P(X < \bar{x} )= P(Z < \bar{x}) = 1 - 0.10\\P(X < \bar{x} )= P(Z < \bar{x}) = 0.90\\

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

\bar{x} = \mu + z(\sigma) \\\bar{x} = 1500 + 1.28(300)\\\bar{x} = 1500 + 384\\\bar{x} = 1884\\

Therefore, you need to score 1884 in order to  qualify for the scholarship.

How to use z-table?

Step 1:

In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2

Step 2:

Then look up at the top of z-table and note down the value of the that column which is 0.08

Step 3:

Finally, note down the intersection of step 1 and step 2 which is 1.28

4 0
3 years ago
the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume
zhuklara [117]
Given:
Population proportion, \mu _{p} = 57% = 0.57
Population standard deviation, σ  = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
SE_{p} =  \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783

The confidence interval is 
\hat{p} \pm z^{*}SE_{p}
where
\hat{p} = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)

Answer: Between 0.417 and 72.4), or between (41% and 72%)

8 0
3 years ago
a shark is 80 feet below the surface of the water. it swims up and jumps out of the water to a height of 15 feet above the surfa
Leni [432]

Answer:

75

Step-by-step explanation:

80+15 is 75

5 0
3 years ago
Rewrite without parenthesis and simplify (y+6)^2
GarryVolchara [31]
Y^2+36, because you square y and 6
4 0
3 years ago
Read 2 more answers
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