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krok68 [10]
3 years ago
8

A 25 foot cable is stretched from the top of an antenna to an anchor point on the ground. How tall is the antenna if the anchor

point is 12 feet from the base of the antenna (rounded to the nearest foot)? A) 20 ft B) 21 ft C) 22 ft D) 23 ft
Mathematics
2 answers:
dexar [7]3 years ago
8 0

Answer:

22

Step-by-step explanation:

aliina [53]3 years ago
4 0
22ft . use pythagoras theorem getting 25ft as your hypotenuse and 12 feet as your adjacent,which will give you a height of 21.9317122ft which when rounded off to nearest foot is 22ft a.
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Translate the sentence into an equation.
coldgirl [10]

Hey there!

We want to multiply a certain quantity by 2, so we will put the two outside of parentheses and put our variable (x) minus two inside the parentheses to represent this. This will all equal two.

2(x-6)=2

The unknown number is also 7.

I hope that this helps!

7 0
3 years ago
Find the volume of this cone.
Katen [24]

Answer:

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3 0
3 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
aleksandr82 [10.1K]

Answer:

Jada error was he multiplied the equation by (-9/4) to make the coefficient of x one. He should have multiplied it by 108

Step-by-step explanation:

Jada solved the equation

-4/9 = x/108

using the steps below:

-4/9 = x/108

(-4/9)(-9/4) = (x/108)(-9/4)

x = -1/48

Jada should have multiplied through by 108, instead of (-4/9). That was the error he made.

Multiplying through by 108 gives

(-4/9)(108) = (x/108)(108)

-48 = x

x = -48

The answer should have been

x = -48

and not

x = -1/48

8 0
3 years ago
Read 2 more answers
Find the perimeter of the quadrilateral.
levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0
2 years ago
if a motercycle is moving at a constant speed down the highway of 40 km/hr, how long would it the motorcycle to travel 10 km
ahrayia [7]

Answer:

15 minutes

Step-by-step explanation:

First, the motorcycle goes at a speed of 40 km/hr.

The question asks for how long it would take to travel 10 km.

Well, there are 60 minutes in an hour, since we will be translating into minutes.

Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.

1/4 of 60 minutes is 15 minutes.  So it takes 15 minutes for the motorcycle to travel 10 km.

Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

\frac{40km}{60min}=\frac{10km}{xmin}

Now cross multiply:

40km*xmin=10km*60min\\40x=600

Divide both sides by 40:

\frac{40x}{40}=\frac{600}{40}\\x=15

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.

6 0
3 years ago
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