Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that 
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
There are 12 boys enrolled in algebra 2
Answer:
We need to use
Step-by-step explanation:
We have to use the equation for passing through the points known as
y2-y1/x2-x1
-1-3/0-5= -4/-5
the answer is 4/5
decimal: 0.8
Draw the triangle and then use Pythagoras' theorem
distance =

= 19.70 (2dp)
Answer:
16/37 I just did this... answer mines pls
Step-by-step explanation: