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andriy [413]
3 years ago
11

Use the graph to determine the domain and range of the relation, and whether the relation is a function

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

domain is correct for b and c

the graph is a function because each value of x has only one y value

hence answer is B

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lianna [129]
No because 7-4 would be 3, then 3/3 is just 1 so the answer would be x=1
3 0
3 years ago
Caroline can sketch 5 cartoon strips in two hours. How long will it take her to sketch 20 strips
liraira [26]

Answer:

8 hours

Step-by-step explanation:

20÷5 = 4

4×2 = 8

Hope this Helps!

:)

6 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
What is 39.79949748 rounded to the nearest hundredth?
Rufina [12.5K]

Answer:

Number = 39.80

Step-by-step explanation:

Given

Number = 39.79949748

Required

Approximate (to the nearest 100th)

This means that, we approximate at the second digit after the decimal.

So:

i.e,

Number = 39.79  [Begin  approximation] 949748

The first digit after [Begin approximation] is then approximated using the following rule:

0 - 4 \approx 0

5 - 9 \approx 1\\

Since 9 falls in 5 - 9 \approx 1\\ category, the number becomes:

Number = 39.[79+1]

Number = 39.80

3 0
3 years ago
Please help me outtttt
QveST [7]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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