The original statement is true!
the converse: If 2 lines do not intersect, they are parallel
the converse is false, the lines could be skew.
Hope this helped :)
Answer:
r = -40
Step-by-step explanation:
1. Move constants to the other side of the equation
r = 16/-.04
2. Simplify (by calculator)
You can use a calculator and plug in 16/-.04
r = -40
2. Simplify (by fraction)
You can turn -.4 into a fraction.
-.04 = - 4/10
r = 16/-(4/10)
r = 16*10/-4
r = -40
Answer:
73 feet.
Step-by-step explanation:
Given:
A rope from the top of a pole is anchored to the ground which is 55 ft away from the base of the pole.
The pole is 48 ft tall.
Question asked:
What is the length of the rope?
Solution:
Here we found that a right angle triangle is formed in which base and height is given <u>as shown in the figure, </u>we have to find the longest side of the triangle,
Base = 55 feet
Height = 48 feet
Length of the rope = ?
By Pythagoras theorem:
Square of longest side = Square of base + Square of height



Taking root both side
![\sqrt[2]{(Longest\ side)^{2} } =\sqrt[2]{5329}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B%28Longest%5C%20side%29%5E%7B2%7D%20%7D%20%3D%5Csqrt%5B2%5D%7B5329%7D)

Thus, length of the rope is 73 feet.
I tried to help hope this helps
Answer:
Sara's speed was 6.4 meters per second faster
Step-by-step explanation:
(Were going to name the olympian steve)
First, we have to find how many <u>meters per second Steve</u> ran. To find this we must divide the number of <u>meters</u> he ran by the <u>amount of time</u> it took him to run all 100 meters.
100 ÷ 9.6 =10.41666667
Since the problem tells us to round to the nearest tenth of a second we round 10.41666667 to 10.4. So now we know how many meters per second Steve ran. Now all we have to do is subtract the number of meters per second Sarah ran, from the number of meters per second Steve ran.
Sarah- 16.8 meters per second
Steve- 10.4 meters per second
16.8-10.4= 6.4
And there you have it! Sarah ran 6.4 meters per second more than Steve. I hope this answer was accurate and helpful. I hope you have an AMAZING day!