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3 years ago

Least common multiple of 9

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

well you cant get the least common mutiple of 9 lol

Step-by-step explanation:

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ABCD is a parallelogram. Find the indicated measure:

uranmaximum [27]

Answer:

12 12 12 12 12 12 12 12 12 1 2 12 12

7 0

3 years ago

According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at

miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

$np=80*0.1=8$

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.173\\\\H_a:\pi$

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578$

This test is a left-tailed test, so the P-value for this test is calculated as:

$P-value=P(z$

As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the percentage is lower in this district.

7 0

3 years ago

Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x

AfilCa [17]

Answer:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0

2 years ago

Evaluate 5a3 + 3b4 when a 4 and b= - 5

valkas [14]

5a^3 + 3b^4

insert the numbers into the equation.

5(4)^3 + 3(-5)^4

evaluate

5(64) + 3(625)

evaluate

320 + 1875

the solution is:

2195

5 0

3 years ago

n^2-2n-3 where n is the number of key rings in thousands, find the number of key rings sold when the profits is $5,000

ArbitrLikvidat [17]

Answer:

For the profit of $5,000, the key chains made is n = 4,000.

Step-by-step explanation:

Here the given expression , where: n = Number of key rings in thousands is given as:

P(n) = n²- 2 n - 3

Now, Profit is given to be $5,000.

Also, as we know 5000 = 5 x (1,000)

⇒ n²- 2 n - 3 = 5

Now, solving the above expression for the value of n, we get:

$n^2 - 2 n - 3 = 5\\\implies n^2 -2n - 8 = 0\\\implies n^2 -4n + 2n - 8 = 0\\\implies n(n-4) + 2(n-4) = 0\\\implies (n-4) (n+2) = 0$

So, n = 4, OR , n = -2

Now, as n = The number of key chains. So it CANNOT BE NEGATIVE.

So, n= 4 = 4 x (1,000) = 4,000 key rings.

Hence, for the profit of $5,000, the key chains made is n = 4,000.

8 0

3 years ago