Answer:
11/381
Step-by-step explanation:
Not sure what the ? after each number means but I'm going to assume they aren't there
so we need find the number of tokens in all which is
44+1414+66=1524
P(red)=44/1524 now reduce giving P(red)=11/381
On Friday, Beth will most likely do 39 sit ups. Every day she is doing an extra 6 sit ups.... Thursday would be 33 sit ups and Friday would be 39 sit ups.
Answer:
Dalton didn't ride any kilometer farther since he keeps threading in the same path as that of his father.
Step-by-step explanation:
If Dalton's dad rode 1 kilometer north, 2 kilometers west 1 kilometer south and 2 kilometers east, then he has been moving in a rectangular path.
If Dalton rode in the same path 5times, then Dalton's has not move farther than his dad since he is still moving in the same rectangular path. He is only expending more energy.
Their final destination will still be the same for both of them no matter how many times Dalton keeps threading in the same path.
Answer:
30 people
Step-by-step explanation:
100 people to the survey. And the question is practically asking how many people are left. So we have to subtract 60 from 100. And then subtract 10.
1.) 100 - 60 = 40
2.) 40 - 10 = 30
Hope this helps you out! : )
The answer is <span>√x + √y = √c </span>
<span>=> 1/(2√x) + 1/(2√y) dy/dx = 0 </span>
<span>=> dy/dx = - √y/√x </span>
<span>Let (x', y') be any point on the curve </span>
<span>=> equation of the tangent at that point is </span>
<span>y - y' = - (√y'/√x') (x - x') </span>
<span>x-intercept of this tangent is obtained by plugging y = 0 </span>
<span>=> 0 - y' = - (√y'/√x') (x - x') </span>
<span>=> x = √(x'y') + x' </span>
<span>y-intercept of the tangent is obtained by plugging x = 0 </span>
<span>=> y - y' = - (√y'/√x') (0 - x') </span>
<span>=> y = y' + √(x'y') </span>
<span>Sum of the x and y intercepts </span>
<span>= √(x'y') + x' + y' + √(x'y') </span>
<span>= (√x' + √y')^2 </span>
<span>= (√c)^2 (because (x', y') is on the curve => √x' + √y' = √c) </span>
<span>= c. hope this helps :D</span>
