All categories

3 years ago

If you vertically stretch the exponential function f(x) = 2X by a factor of 5, what

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

The answer to your question is A

You might be interested in

Given a=5 b=12 c=13 5²+12²=13²

Advocard [28]

Answer:

a^2+b^2=a(2)^1.5

Step-by-step explanation:

im not sure, just seems right

4 0

3 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

If angle 4 is measured to be 70 degrees, then select all of the other angles that would also be 70 degrees in the diagram shown.

m_a_m_a [10]

The answer are angles 1, 4, 5, and 8

5 0

4 years ago

Read 2 more answers

Indicate, in standard form, the equation or inequality that is shown by the graph. (0,4)(4,0)

Len [333]

(0,4)(4,0)
slope = (0 - 4) / (4 - 0) = -4/4 = -1

y = mx + b
slope(m) = -1
use either of ur points....(0,4)...x = 0 and y = 4
sub and find b, the y int
4 = -1(0) + b
4 = b

equation is : y = -x + 4....in standard form, it is : x + y = 4

3 0

4 years ago

Read 2 more answers

I need help for this also

lubasha [3.4K]

Answer:

a) h = 6 2/17

b) k = 3 8/17

Step-by-step explanation:

We can make a list of corresponding sides:

AB (17 cm) and DE (13 cm)

BC (15 cm) and EC (8+k cm)

CA (8 cm) and CD (h cm)

Because the triangles are similar, we know corresponding sides are proportional.

CD/CA = DE/AB

h/8 = 13/17

h = 8(13/17) = 6 2/17

EC/BC = DE/AB

(8+k)/15 = 13/17

8 +k = 15(13/17)

k = 11 8/17 -8 = 3 8/17

5 0

3 years ago