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chubhunter [2.5K]
4 years ago
5

(ax + b) × (cx + d) =

Mathematics
2 answers:
Stolb23 [73]4 years ago
7 0
These are easy if you know  " FOIL ".  That's a procedure that takes you through multiplying two binomials.

FOIL stands for
-- <u><em>F</em></u>irst terms
<span>-- </span><u><em>O</em></u>utside terms
<span>--<em> </em></span><u><em>I</em></u>nside terms
<span>--<em> </em><u><em>L</em></u></span>ast terms

and that's how you keep everything straight while you're doing it.

(ax + b) x (cx + d)

Multiply First terms . . . 'ax' times 'cx' =  <em>acx²</em>

Multiply Outside terms . . . 'ax' times 'd'  =  <em>adx</em>

Multiply Inside terms . . .  'b' times 'cx'  =  <em>bcx</em>

Multiply Last terms . . .  'b' times 'd' =  <em>bd</em>

Now addummup:

(ax + b) x (cx + d)  =  <em>acx² + adx + bcx + bd</em>

From there, you can look for opportunities to make it look cleaner and prettier ... factoring, combining like terms, etc.

gavmur [86]4 years ago
3 0
A * c *x^{2}  +  a * x *d  +  b * c* x  +  b * d  = acx^{2} + ( ad + bc)x + bd.
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