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Romashka-Z-Leto [24]
3 years ago
6

....................

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

<em>C:</em><em> </em><em>is</em><em> </em><em>co</em><em>rrect</em><em> answer</em>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em>3 \times  {10}^{5}</em>

coldgirl [10]3 years ago
7 0

Answer:

C.is the correct answer

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ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of -8x^2y^3 \div xy.

-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}

                    =\frac{-8\times x\times x\times y\times y\times y}{xy}

Taking common term xy outside in the numerator.

                    =\frac{xy(-8\times x\times y\times y)}{xy}

Both xy in the numerator and denominator are cancelled.

                    =-8xy^2

Thus, the quotient of -8x^2y^3 \div xy is -8xy^2.

Given the quotient of -8x^2y^3 \div xy is same as the product  of 4xy and ____.

-8xy^2=4xy × missing term

Divide both sides by 4xy, we get

⇒ missing term = \frac{-8xy^2}{4xy}

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