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Vinil7 [7]
3 years ago
7

Perfect Square Greater Than the Number 11

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

16

Step-by-step explanation:

4x4=16

Aliun [14]3 years ago
4 0
11 is not a perfect square :)
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I'm not sure what to do about this problem, so please help me out.
vivado [14]

Answer:

21

Step-by-step explanation:

Let the three consecutive integers be;

    x , x + 1 and x + 2:

The sum of squares of the two smaller numbers:

  The two smaller numbers are x and x+ 1

Sum of their squares:

           x² + (x+1)²;

        x² + x² + 2x + 1 = 2x² + 2x + 1

It is 45 more than the square of the larger number:

    Larger number = x + 2

        (x+2)² = x² + 4x + 4

 45 more;

        x² + 4x + 4 + 45  = x² + 4x + 49

Both are equal:

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  2x² - x² + 2x - 4x + 1 - 49 = 0

      x² - 2x - 48 = 0

      x² - 6x + 8x - 48 = 0

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      x + 8 = 0 or x - 6 = 0

      x  = -8 or x = 6

We choose x = 6 because it makes the solution true as a positive integer

  Sum of the three numbers:

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7 0
4 years ago
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