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4 years ago

Write (picture included) as a complex number in standard form.

Mathematics

1 answer:

vredina [299]4 years ago

6 0

Answer:

-9/4 -4i

Step-by-step explanation:

-3i + 3/4 + 2i -(3+ 3i)

The first step is to simplify the terms

-3i + 3/4 + 2i -(3+ 3i)

Now we distribute the negative sign

-3i + 3/4 + 2i -3- 3i

Now combine like terms

3/4 -3 -3i+2i -3i

-2 1/4 -4i

Change the mixed number to an improper fraction.

-(4*2+1)/4 -4i

-9/4 -4i

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3 years ago

Hi everyone I was wondering if someone could please help me out with this problem and explain it to me

PSYCHO15rus [73]

Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord

OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:

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4 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

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Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

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Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

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3 years ago

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Answer:

Step-by-step explanation:

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