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3 years ago

A pool measuring 8 meters by 28 meters is surrounded by a path of uniform width,

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

7 0

6 will be you answer

Sindrei [870]3 years ago

4 0

Answer:

Step-by-step explanation:

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The lengths of the sides of a triangle are 3, 4, 5. Can the triangle be a right triangle?

Contact [7]

Answer:

Yes it can

Step-by-step explanation:

To check wether it's a right angle triangle we need to apply the Pythagoras theorem

h^2= a^2 +b^2

Hypotenuse is always the longest side so

5^2 = 3^2 + 4^2

This is correct, so the triangle is a right angle triangle

Answer from Gauthmath

3 0

3 years ago

Simplify. -9 -5 -7 х Y Z 2 6 3 X Y Z

krok68 [10]

Answer:

$= {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

Step-by-step explanation:

$= \frac{ {x}^{ - 9} {y}^{ - 5} {z}^{ - 7} }{ {x}^{2} {y}^{6} {z}^{3} } \\ = {x}^{ - 9 - 2} {y}^{ - 5 - 6} {z}^{ - 7 - 3} \\ = {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

7 0

3 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

3 0

3 years ago

Answer ,how to do it.

guapka [62]

Answer:

The system has two solutions:

x₁ = 5 ⇒ y₁ = -10

x₂ = -2 ⇒ y₂ = 11

Step-by-step explanation:

Let's solve the system of equations, this way:

y = -3x + 5

y = x ² - 6x - 5

Replacing y in the 2nd equation:

y = x ² - 6x - 5

-3x + 5 = x ² - 6x - 5

x ² - 3x - 10 = 0

Solving for x, using the quadratic formula:

(3 +/- √(9 -4 * 1 * -10))/2 * 1

(3 +/- √9 + 40)/2

(3 +/- √49)/2

(3 +/- 7)/2

x₁ = 10/2 = 5

x₂ = -4/2 = -2

x₁ = 5 ⇒ y₁ = -10

x₂ = -2 ⇒ y₂ = 11

As we can see the system has two different solutions

8 0

3 years ago

A N O T H E R O N E

guapka [62]

Answer:

ksajcsxkb asljbas akajs

Step-by-step explanation: sxakn skdj

4 0

3 years ago