1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
Answer:
m=0
Step-by-step explanation:
i think?
Answer:
They are even numbers (divisible by two)
Step-by-step explanation:
The number column starts from 2 and is incremented by two for every number in the column. The remainder of the division of each number in the sequence is zero and the result of the division is sequence 1,2,3,4,5,6,7...
Therefore, the numbers in the column are even numbers.
Answer:
I think you meant for the plus sign in the second problem to be an = sign so the equation looks like this y=-x+4
If so your answer is A the first graph
I graphed it on desmos calculator
98 98/100 because you move the decimal point over 2 times
