Question

Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 13.5 ◦ . If the screen is 154 cm from the double-slit, how far apart is this bright band from the central peak? Answer in cm.

Answer 1

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is $D=154 cm$

Wavelength $\lambda =348 nm$

Angle between zeroth order bright fringe and Fourth-order bright fringe is $\theta =13.5^{\circ}$

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

$y_n=\frac{nD\lambda }{d}$

Also $\tan \theta =\frac{y_4}{D}$

$y_4=\tan (13.5)\cdot 1.54$

$y_4=0.24\times 1.54$

$y_4=0.369 m$