Answer: x = -3/4 can not be a rational zero of the polynomial.
Step-by-step explanation:
We have the polynomial:
6x^5 + ax^3 -bx -12 = 0.
The theorem says that:
If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).
The factors of -12 (different than itself) are (independent of the sign).
1, 2, 3, 4 and 6.
So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.
The factors of 6 are:
1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.
Then the option that can not be a zero of the polynomial is
x = -3/4
because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.
Answer:
23, 15 and 45
Step-by-step explanation:
a+b+c = 83
a = b + 8
c = 3*b
(b+8) + b + 3*b = 83
5*b + 8 = 83
5*b = 75
b = 15
a = b + 8 = 15 + 8 = 23
c = 3*b = 3*15 = 45
Verification
a+b+c = 23 + 15 + 45 = 83; correct
Answer:
87.03%
Step-by-step explanation:
You have to find out how much is 10% of 96.7.
So 96.7 x 0.10 = 9.67
Since you're getting a 0 then you directly subtract that from the 96.7% you have.
The answer also has to do with the total grade and total assignments done but that info is not provided
