29.
As 
, 
.
This can be easily verified by looking at the graph (graph of a quadratic equation).
30.
The growth of a population is not linear, it's exponential.
31.
Exponential growth > polynomial, so 
.
35.
The question is asking V(t) for t = 40.
36.
The point of symmetry of a quadratic equation 
is at its vertice:
The line is x= 3.
Answer:
0.95, 2.15
Step-by-step explanation:
cookie-x
ice bar-y
7x+2y=10.95 (*3)
4x+3y=10.25 (*2)
21x+6y=32.85
8x+6y=20.5
21x-8x=32.85-20.5=12.35
13x=12.35
x=0.95
2y=10.95-7*0.95=4.3
y=2.15
51,007.
If you want it is thousandths,
7.051.
Bye!
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
