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Yakvenalex [24]
2 years ago
8

What is the solution to the equation 1/4x = 5?

Mathematics
1 answer:
puteri [66]2 years ago
5 0
The solution to your equation is:

Solve:
1/4x = 5

Step 1: Multiply both sides by 4
4 * (1/4x) = (4) * (5)

x = 20


Thus your answer is:

Letter Choice (C), x = 20





Hope that helps!!!



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Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ​ ≈ 3.14 and round your answer t
tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0
3 years ago
Find the derivative F(x)=(5x+3)(2x^2+1)
Lerok [7]

Answer:

10x^3 + 6x^2 + 5x + 3

Step-by-step explanation:

F(x)=(5x+3)(2x^2+1)

= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1

= 10x^3 + 5x + 6x^2 + 3

= 10x^3 + 6x^2 + 5x + 3

3 0
3 years ago
125% of what number is 50?<br> 125% of is 50.<br> (Type a whole number.)
horsena [70]

Answer:

i thinkkk 40

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4 0
2 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
12345678910 Using the greatest common factor for the terms, how can you write 80 + 32 as a product?
Romashka-Z-Leto [24]
Find the GCF of 80 and 32.  

I'd start by identifying possible integer factors of both 80 and 32:
80:  {1,2,4,5,8,10,16,20, 40, 80}

32:  {1, 2,4, 8, 16, 32}

Working backwards, we see that the first factor that is represented in both lists is 16.  Is 80 evenly divisible by 16?  Yes; the quotient is 5.
                  Is 32 evenly divisible by 16?  Yes; the quotient is 2.

You could writet 80 + 32 as 16(5 + 2).  This is a product equal to 112, just as 80 + 32 = 112.
5 0
3 years ago
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