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umka21 [38]
4 years ago
8

What quadrant would the ordered pair (–4,–6) fall in?

Mathematics
2 answers:
guapka [62]4 years ago
7 0

Answer:

The ordered pair (-4,-6) is in the 3rd quadrant

Step-by-step explanation:

If we have an ordered pair (a,b), they would fall in:

  • 1st quadrant: if a and b are positive
  • 2nd quadrant: if a is negative and b is positive
  • 3rd quadrant: if a and b are negative
  • 4th quadrant: if a is positive and b is negative

Then, taking into account that -4 and -6 are negative numbers, the ordered pair (-4,-6) belong to the 3rd quadrant

sveta [45]4 years ago
3 0
QUADRANT 3 IS the right answer
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Represent the following expressions as a power of the number a where a≠0 a^2*(a^4)^3÷a^13
ivann1987 [24]

Answer:

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Step-by-step explanation:

  • a^2*(a^4)^3:a^{13}=
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4 0
3 years ago
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How can i get the answer to 5(2x -3) by using distributive property??.. pls help im stuck
Leto [7]

Answer:

to use the distributive property, you would multiply 2x and -3 by 5. this would leave the equation as 10x-15

Step-by-step explanation:

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5 0
3 years ago
Can anyone solve this for me? and show how you got that answer?
Mashutka [201]

53=20+x

Subtract 20 from 20 and 53

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Hope this helps!

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6 0
3 years ago
Benjamin is trying to find the height of a radio antenna on the roof of a local building.
xz_007 [3.2K]

The height of the antenna on the roof of the local building is approximately 8 meters.

The situation forms a right angle triangle.

<h3>Properties of a right angle triangle:</h3>
  • One of its angles is equals to 90 degrees
  • The sides of the triangles can be calculated using Pythagoras theorem.

Therefore, let's find the height of the building and the radio antenna from the eye point.

Using trigonometric ratios,

tan 40° = opposite / adjacent

tan 40° = x / 25

where

x = the height of the building and the radio antenna from the eye point.

x = 25 tan 40

x = 25 × 0.83909963117

x = 20.9774907794 meters

Let's find the height of the building from his eye point.

tan 28° = y / 25

where

y = height of the building from his eye point

y = 25 × tan 28°

y = 25 × 0.53170943166

y = 13.2927357915 meters

Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786

Height of the antenna ≈ 8 meters

learn more on elevation here: brainly.com/question/17582385?referrer=searchResults

8 0
3 years ago
HELP PLEASE ASAP!!!<br><br> I NEED HELP AS SOON AS POSSIBLE PLEASE!
Alex

Answer:

c,d,a

Step-by-step explanation:

5 0
3 years ago
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