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Westkost [7]
3 years ago
9

I need answer please

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Trigonometric identities:

\sin^{2} (x)  +  { \cos}^{2} (x) = 1 \\  {\cos}^{2} (x) = 1 -  { \sin}^{2} (x) \\   { \sin }^{2} x = 1 - {\cos}^{2} (x) \:

Replace into the equation

\frac{ \sqrt{1 -  \cos^{2} (x) } }{ \sin(x) }  +  \frac{ \sqrt{1 -  \sin^{2}(x) } }{ \cos(x) }   \\ \\   =  \frac{ \sqrt{ \sin^{2}(x) } }{ \sin(x) }  +  \frac{ \sqrt{ \cos^{2}(x) } }{ \cos(x) }

Remove roots and simply

=  \frac{ \sin(x) }{ \sin(x) }  +   \frac{ \cos(x) }{ \cos(x) }  \\  \\  = 1 + 1 \\  = 2

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