If
is the variable of the horizontal axis, then you can solve for
to get the equation of the line in slope-intercept form in the
plane:
i.e. a line with slope
through the origin, which means it is contained in the first and third quadrants. Since the terminal side of
has a negative sine, the angle must lie in the third quadrant.
Because the slope of the line is
, you can choose any length along the line to make up the hypotenuse of a right triangle with reference angle
. Any such right triangle will have
, regardless of whether the angle is the first or third quadrant. But since
is known to lie in the third quadrant, and so
and
are both negative, you have
Answer:
n=3p
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
B.
Step-by-step explanation:
Because of isosceles triangle, AB = CB.
Because of the median, AD = CD.
Because of congruence of segments being reflexive, BD = BD.
By SSS, the triangles BAD and BCD are congruent.
Answer: B.
For the first equation it should be 1 and 4 because 7(1)+6(4) would simplify to 7+24 which equals 31.
Then for the second equation, well... there’s multiple answers:
First would be 3 and -2 because 3(3)-10(-2) simplifies to 9+20=29.
Another one would be 23 and 4 because 3(23)-10(4) simplifies to 69-40=29.
Hopefully this helps :D
Answer:
-60
Step-by-step explanation:
The objective is to state whether or not the following limit exists
.
First, we simplify the expression in the numerator of the fraction.
Now, we obtain
and the fraction is transformed into
Therefore, the following limit is
You can plug in 
in the equation, hence
