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Greeley [361]
2 years ago
8

Which of the following is an arithmetic sequence​

Mathematics
1 answer:
ad-work [718]2 years ago
6 0

Answer:

C

Step-by-step explanation:

For it be an arithmetic sequence it must either be going up by the same number each time or down by the same number each time.

Lets look at the choices:

A. From 2 to 3 that went up by 1. But from 3 to 7, that doesn't continue to go up by 1. So this sequence is not arithmetic.

B. From 2 to 4, that went up by 2. But from 4 to 16, that doesn't continue to go up by 2. So this sequence is not arithmetic.

C. From 3 to 0, that goes down by 3. From 0 to -3, that goes down by 3. From -3 to -6, thar goes down by 3. This sequence is arithmetic.

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Rewrite 2 2/5 as an improper fraction. helpp
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Answer: 12\5 :)

Step-by-step explanation: :)

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I can have multiple<br> different representations.<br> All 6 of my faces are<br> square.
Dafna11 [192]

Answer:

Find the area of the trapezoid below.

Step-by-step explanation:

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Suppose that the waiting time for a license plate renewal at a local office of a state motor vehicle department has been found t
Wittaler [7]

Answer:

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the waiting time in minutes of a population, and for this case we know the distribution for X is given by:

X \sim N(30,8)  

Where \mu=30 and \sigma=8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

7 0
3 years ago
Writing an equation of the form A/x+B)C to solve a word probl...
Margarita [4]

Answer:

(a) The equation is 7h-2=56.

(b) Trey gets approximately $8.29 for each hour of work.

Step-by-step explanation:

Given:

Number of hours Trey works = 7

Amount of money he put aside for mom = $2

Total Amount he keeps each day = $56

We need to find the amount he gets for each hour.

Let 'h'  represent the amount (in dollars) Trey gets paid each hour.

Solving for part (a).

We need to write the equation to find the amount he gets paid for each hour.

Now we can say that;

Total Amount he keeps each day is equal to Number of hours Trey works multiplied by the amount he gets paid for each hour minus Amount of money he put aside for mom.

framing in equation form we get;

7h-2=56

Hence the equation is 7h-2=56.

Solving for part (b).

we need to solve the above equation to find the amount he gets paid for each hour.

On solving the equation we get;

Adding both side by 2 we get

7h-2+2=56+2\\\\7h=58

Now Dividing both side by 7 using Division Property we get;

\frac{7h}{7} = \frac{58}{7}\\\\h \approx \$8.29

Hence Trey gets approximately $8.29 for each hour of work.

7 0
2 years ago
3. If dy = x^2y^2 , then what is d2y/dx2
lakkis [162]

\text{Given that,}\\\\\dfrac{dy}{dx} = x^2 y^2\\\\ \implies \dfrac{d^2 y}{dx^2} = x^2\cdot  2y \dfrac{dy}{dx}+ y^2 \cdot 2x\\\\\implies \dfrac{d^2 y}{dx^2} = x^2 \cdot  2y \cdot x^2 y^2  +2xy^2\\\\\implies \dfrac{d^2 y}{dx^2} =2x^4y^3 + 2xy^2 = 2xy^2(x^3y+1)

5 0
2 years ago
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