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3 years ago

When one element replaces another element in a compound the reaction is a___ reaction

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

Answer:

single replacement lol

Step-by-step explanation:

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The graph of equation (3,-2) passes through which point

Licemer1 [7]

Answer:

If the y-intercept is 0, then this graph passes through [3,-2][6,-4][9,-6] and so forth.

Step-by-step explanation:

Rise over run, 3 is the rise, and -2 is the run. Using this you can find any point on the line up to infinity.

7 0

3 years ago

Read 2 more answers

2x-3x^3+8 in standard form

larisa [96]

3x³ -2x - 8 = 0

......,...........,

8 0

3 years ago

Fudgin [204]

Triangle DEF hope that helps

4 0

3 years ago

Solve for x in the equation.

labwork [276]

Answer:

The solution is $\displaystyle x=1\pm \sqrt{47}$ . Fourth option

Explanation:

Solve for x:

$2x^2+3x-7=x^2+5x+39$

Move all the terms from the right to the left side of the equation, a zero in the right side:

$2x^2+3x-7-x^2-5x-39=0$

Join all like terms:

$x^2-2x-46=0$

The general form of the quadratic equation is:

$ax^2+bx+c=0$

Solve the quadratic equation by using the formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

$\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}$

$\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}$

$\displaystyle x=\frac{2\pm \sqrt{188}}{2}$

Since 188=4*47

$\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}$

Take the square root of 4:

$\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}$

Divide by 2:

$\displaystyle x=1\pm \sqrt{47}$

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

8 0

3 years ago

Question D- If the area of a square is 121 square centimeters, what is its side length?

Ipatiy [6.2K]

The formula for the area of a square is the side squared, or multiplied together.

Basically, if the side length is x, the area is x*x or x^2.

We can use that to set up an equation.

x^2=121
x=square root of 121=11

Hope this helps!

3 0

3 years ago