To move a graph up, you need to add the units tot he end of the equation.
The graph of f(x) is f(x) = 15x+60
So add 12 to the equation to get g(x) = 15x +72
The answer would be A.
I think it’s linear. no numbers repeat. i could be wrong but LOL
Answer:
Step-by-step explanation:
![\text{Use}\\\\a^\frac{m}{n}=\sqrt[n]{a^m}\\\\a^n\cdot a^m=a^{n+m}\\-----------------\\\\length=\sqrt[3]{81}=\sqrt[3]{3^4}=3^\frac{4}{3}\\\\width=3^\frac{2}{3}\\\\\text{The area of a rectangle:}\ A=width\cdot length.\\\text{Substitute:}\\\\A=3^\frac{4}{3}\cdot3^\frac{2}{3}=3^{\frac{4}{3}+\frac{2}{3}}=3^{\frac{4+2}{3}}=3^\frac{6}{3}=3^2=9](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5Ca%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D%5C%5C%5C%5Ca%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C-----------------%5C%5C%5C%5Clength%3D%5Csqrt%5B3%5D%7B81%7D%3D%5Csqrt%5B3%5D%7B3%5E4%7D%3D3%5E%5Cfrac%7B4%7D%7B3%7D%5C%5C%5C%5Cwidth%3D3%5E%5Cfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%5Ctext%7BThe%20area%20of%20a%20rectangle%3A%7D%5C%20A%3Dwidth%5Ccdot%20length.%5C%5C%5Ctext%7BSubstitute%3A%7D%5C%5C%5C%5CA%3D3%5E%5Cfrac%7B4%7D%7B3%7D%5Ccdot3%5E%5Cfrac%7B2%7D%7B3%7D%3D3%5E%7B%5Cfrac%7B4%7D%7B3%7D%2B%5Cfrac%7B2%7D%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B4%2B2%7D%7B3%7D%7D%3D3%5E%5Cfrac%7B6%7D%7B3%7D%3D3%5E2%3D9)
B = 7/8(A-9)
first you must distribute
B = 7/8A -7 7/8
add over the -7 7/8
B + 7 7/8 = 7/8A
now divide both sides by 7/8
B+7 7/8
----------- = A
7/8
