Answer:
A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.
Step-by-step explanation:
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(4,7.8) is your answer please give brainliest!
The mean is 0.0118 approximately. So option C is correct
<h3><u>Solution:</u></h3>
Given that , The probability of winning a certain lottery is
for people who play 908 times
We have to find the mean number of wins

Assume that a procedure yields a binomial distribution with a trial repeated n times.
Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.



Hence, the mean is 0.0118 approximately. So option C is correct.