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nadya68 [22]
3 years ago
8

Perfect Plumbing Corporation currently manufactures a valve for use in water pumps that it produces for sale. The company is con

sidering purchasing the valves from an outside supplier rather than manufacturing them. Which of the following costs is not relevant to the decision?
A. The cost of direct material required to make the valve.
B. The price charged by the outside supplier for an identical valve.
C. The cost of the machinery owned by Perfect Plumbing used exclusively to manufacture this valve.
D. The salvage value of the machinery owned by Perfect Plumbing used exclusively to manufacture this valve.
Business
1 answer:
andriy [413]3 years ago
7 0

Answer:

Perfect Plumbing Corporation currently manufactures a valve for use in water pumps that it produces for sale. The company is considering purchasing the valves from an outside supplier rather than manufacturing them. Which of the following costs is not relevant to the decision?

The cost of direct material required to make the valve.

Explanation:

Since perfect plumbing corporation intended to buy rather than to manufacture then the cost of direct material required to make the valve is none of there concern. The would only purchase and sell at price that suits them

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Answer:

Explanation:

Experiments were performed for 240 people, 60 people test positive.

Step 1: we calculate the sample proportion; p= 60/240= 0.25.

Step 2: calculate the standard error for the sample, which is the square root of sample proportion,p = p(1-p)/n, n=100

0.25(1-0.25)/100

= 0.04.

Step 3: calculate the test statistics; assuming the hypothesis test percentage is 25%

Then, we say 0.25-1=0.75

-0.75/0.04

= -1.875.

In particular, the sample results are -1.875 standard error.

Probability of Z is less than -1.875.

Look up it value in the Z table

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A job can be done with Machine A that costs $12,500 and has annual end-of-year maintenance costs of $5000; its salvage value aft
sdas [7]

Answer and Explanation :

As per the data given in the question,

Present value = Amount ÷ (1 + r)^n

Machine A

Year           Amount        Discount Factor      PV

1                  $5,000           1.05                  $4,761.90

2                $5,000                                     $4,535.15

3               $5,000                                      $4,319.19

Total                                                          $13,616.24

Now

Present value of salvage value =$2,000 ÷ 1.05^3 = $1,727.68

Present worth of Machine A is

= -$12,500 - $13,616.24 + $1,727.68

= -$24,388.56

Similarly Present worth of Machine B = -$15,000 - $4,000 ÷ 1.05 -$4,000 ÷ (1.05)^2 - $4,000 ÷ 1.05^3 - $4,000 ÷ 1.05^4 + $1,500 ÷ 1.05^4

=-$24,658.94

Based on the comparison between Machine A and Machine B

Machine A is better because it has higher present worth

Annual worth:

For machine A = -$12,500(A/PA,5%,3) -$5,000+$2,000(A/F,5%,3)

=-$12,500 × 0.367 - $5,000 + $2,000 × 0.317

= -$8,953.5

For Machine B:

=  -$15,000(A/P,5%,4) - $4,000 + $1,500(A/F,5%,4)

= -$7,882.16

Based on the comparison between Machine A and Machine B

Machine B is better because it has higher annual worth

Capitalized cost:

Machine A :

= -$12,500+$2,000(P/F,5%,3) - $5,000 ÷ 0.05

=  -$12,500 + $2,000 × 0.86 - $5,000 ÷ 0.05

= -$110,772

Machine B :

=-$15,000(P/F,5%,4) - $4000 ÷ 0.05

=-$15,000 × 0.82 - $4,000 ÷ 0.05

= -$93,765.9

Based on the comparison between Machine A and Machine B

Machine B is better because it has lower capitalized cost

3 0
3 years ago
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