Answer:
4.71 minutes
Step-by-step explanation:
Incomplete question [See comment for complete question]
Given
Shape: Cone
-- radius
--- height
![Rate = 14in^3/min](https://tex.z-dn.net/?f=Rate%20%3D%2014in%5E3%2Fmin)
Required
Time to pass out all liquid
First, calculate the volume of the cone.
This is calculated as:
![V = \frac{1}{3} \pi r^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2h)
This gives:
![V = \frac{1}{3} * 3.14 * 3^2 * 7](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%203.14%20%2A%203%5E2%20%2A%207)
![V = \frac{1}{3} * 197.82](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20197.82)
![V = 65.94in^3](https://tex.z-dn.net/?f=V%20%3D%2065.94in%5E3)
To calculate the time, we make use of the following rate formula.
![Rate = \frac{Volume}{Time}](https://tex.z-dn.net/?f=Rate%20%3D%20%5Cfrac%7BVolume%7D%7BTime%7D)
Make Time the subject
![Time= \frac{Volume}{Rate }](https://tex.z-dn.net/?f=Time%3D%20%5Cfrac%7BVolume%7D%7BRate%20%7D)
This gives:
![Time= \frac{65.94in^3}{14in^3/min}](https://tex.z-dn.net/?f=Time%3D%20%5Cfrac%7B65.94in%5E3%7D%7B14in%5E3%2Fmin%7D)
![Time= \frac{65.94in^3}{14in^3}min](https://tex.z-dn.net/?f=Time%3D%20%5Cfrac%7B65.94in%5E3%7D%7B14in%5E3%7Dmin)
Cancel out the units
![Time= \frac{65.94}{14} min](https://tex.z-dn.net/?f=Time%3D%20%5Cfrac%7B65.94%7D%7B14%7D%20min)
![Time= 4.71 min\\](https://tex.z-dn.net/?f=Time%3D%204.71%20min%5C%5C)
Answer:
The answer to your question is: AC = 20
Step-by-step explanation:
Data
AB = 2x - 4
BC = 4x
AC = 2x + 12
AC = ?
AB + BC = AC
2x - 4 + 4x = 2x + 12
6x - 4 = 2x + 12
6x - 2x = 12 + 4
4x = 16
x = 16/4
x = 4
AB = 2(4) - 4 = 8 - 4 = 4
BC = 4(4) = 16
AC = 2(4) + 12 = 8 + 12 = 20
4 + 16 = 20
20 = 20
Hello!
In terms of Order of Operations, you would multiply 8 and 4 as it is the first multiplication or division step in the problem.
The answer is B) multiply 8 by 4
Hope this helps!
Answer:
1. y =6 2. y=4+2x
Step-by-step explanation:
Answer:
10 times
Step-by-step explanation:
the 6 in 65 equals 60