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Sloan [31]
4 years ago
8

Please help I don't even understand the question, I need help ASAP!

Mathematics
1 answer:
Iteru [2.4K]4 years ago
6 0

Answer:

i think it is

divide by 10

subtract 10

subtract 18

divide by 5

Step-by-step explanation:

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The temperature went from -16°F to 7°F. What was the change in temperature?
worty [1.4K]

Answer:

To find this out, we first need to see the change, is it a positive change or a negative change? Well in this case, as the temperature is increasing, we find that the change is positive. The next step we need to do, id that, how much was the change by, we can find this out by finding the absolute value of the difference of -16°F and 7°F

The absolute value means, the operations answer has to be positive, if not then it will become positive.

|-16°F -7°F|

=> |-23°F|

=> 23°F

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

4 0
3 years ago
Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
3 years ago
Is -1.2 a rational number
Taya2010 [7]

Answer:

I don't think so

Step-by-step explanation:

5 0
3 years ago
pH measurements of a chemical solutions have mean 6.8 with standard deviation 0.02. Assuming all pH measurements of this solutio
aalyn [17]

Answer: 2.14 %

Step-by-step explanation:

Given : pH measurements of a chemical solutions have

Mean :  \mu=6.8

Standard deviation : \sigma=0.02

Let X be the pH reading of a randomly selected customer chemical solution.

We assume  pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).

The z-score for the normal distribution is given by :-

z=\dfrac{x-\mu}{\sigma}

For x = 6.74

z=\dfrac{6.74-6.8}{0.02}=-3

For x = 6.76

z=\dfrac{6.76-6.8}{0.02}=-2

The p-value =P(6.74

P(z

In percent, 0.0214\times=2.14\%

Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%

6 0
4 years ago
10 pens for $8.99. <br> 25 pens for $19.75
rewona [7]

What is the question?

Step-by-step explanation:

4 0
3 years ago
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