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Greeley [361]
4 years ago
6

A right rectangular prism is packed with cubes of side length fraction 1 over 5 inch. If the prism is packed with 15 cubes along

the length, 6 cubes along the width, and 5 cubes along the height, what is the volume of the prism?
Mathematics
1 answer:
Helen [10]4 years ago
4 0

Answer:

3.6 in³

Step-by-step explanation:

If each cube is 1/5 inch:

15 cubes along the length = 15÷5 = 3 inches

5 cubes along the height = 5÷5 = 1 inch

6 cubes along the width = 6÷5 = 1.2 inches  (1 and 1/5)

V=lwh=3*1*1.2= 3.6 in³

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Simplify: 7.3 times 11/4
zavuch27 [327]

Answer:

20.075

Step-by-step explanation:

7.3 * 11/4 =

7.3 * 2.75 =

20.075

4 0
4 years ago
A skilled chess player believes that when they play a novice opponent, there is a 90% probability they will be able to beat them
zavuch27 [327]

Answer:

b) Binomial

c) Poisson

Step-by-step explanation:

The geometric distribution is the number of trials required to have r successes. The measures the number of sucesses(wins), not the number of trials required to win r games. So the geometric distribution does not apply.

For each match, there are only two possible outcomes, either the skilled player wins, or he does not. The probability of the skilled player winning a game is independent of other games. So the binomial distribution applies.

We can also find the expected number of wins of the skilled player, which is 15*0.9 = 13.5. The Poisson distribution is a discrete distribution in which the only parameter is the expected number of sucesses. So the Poisson distribution applies.

So the correct answer is:

b) Binomial

c) Poisson

7 0
4 years ago
Read 2 more answers
Complete the statements describe how to convert feet to yards to find the number of yard like the number of feet by the unit rat
Snezhnost [94]

Answer:

  • divide
  • 3 ft/yd

Step-by-step explanation:

To find the number of yard, <em><u> divide </u></em> the number of feet by the unit rate <em><u> 3 </u></em> feet per yard.

6 0
3 years ago
How do i write 304,967,000 in word form
kakasveta [241]
Three hundred four million nine hundred sixty seven thousand
5 0
4 years ago
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What is the 4th term of the expanded binomial (2x – 3y)^6
san4es73 [151]

Answer:

The 4th term of the expanded binomial is -4320x^3y^3

Step-by-step explanation:

Considering:

$ (x+y)^n = \sum_{k=0}^{n} \binom{n}{k}  x^{n-k}y^k$

$ (2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k}  (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of k

$ (2x-3y)^6 = \binom{6}{0}  (2x)^{6-0}(-3y)^0     +       \binom{6}{1}  (2x)^{6-1}(-3y)^1     +      \binom{6}{2}  (2x)^{6-2}(-3y)^2   +   \\ $

$\binom{6}{3}  (2x)^{6-3}(-3y)^3    +    \binom{6}{4}  (2x)^{6-4}(-3y)^4    +  \binom{6}{5}  (2x)^{6-5}(-3y)^5    +    \binom{6}{6}  (2x)^{6-6}(-3y)^6            $

I will not write every product, but just solve following the steps:

For k=0

$\binom{6}{0}  (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)}   (2x)^{6-0}(-3y)^0$

$ \frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

64x^6

(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6

8 0
3 years ago
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