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Mandarinka [93]
4 years ago
12

If 15 grams of an organic solid is dissolved in 80 mL of water, how many grams remain in the water after extraction with 50 mL o

f a solvent which has a partition (distribution) coefficient with water of 8? Show calculations.
Chemistry
1 answer:
kumpel [21]4 years ago
4 0

Answer:

2.5 g

Explanation:

The partial coefficient (K) is the ratio of the solubility (S) of a solute in two different solvents. For the given problem:

K = Ssolvent/Swater

The solubility is the mass divided by the volume. If the fraction of the solute in water is called q, the fraction of it in the solvent is 1-q. Let's call m the initial mass of the solute, so, after the extraction:

mass at the solvent = (1-q)m

mass at water = qm

Ssolvent = (1-q)m/50

Swater = qm/80

8 = [(1-q)m/50]/qm/80

8 = 80*(1-q)/50q

400q = 80 - 80q

480q = 80

q = 0.167

The mass that remains at the water is:

0.167*15 = 2.5 g

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what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th
serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe ------------------ 207 g of XeF₄

                     130 g of Xe  -------------------  x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0
3 years ago
45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Alex Ar [27]

45.6 mL of 0.0600 M of Ba(OH)_{2} is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : M_{1} V_{1} =  M_{2} V_{2}                 ...( 1 )

Where  M_{1}= concentration of Ba(OH)_{2}  =  0.0600 M ( given )

M_{2} = concentration of HCl = ? ( to be find )

 V_{1}= volume of Ba(OH)_{2}  = 25.0 mL  ( given )

V_{2} = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  M_{2}  × 45.6 mL

M_{2}  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

to learn about concentration here ,

brainly.com/question/10725862

#SPJ1

7 0
1 year ago
Why is7/2 ther in this equation and what can i do to make it a whole no? C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O
ExtremeBDS [4]
You can Multiply the whole equation with 2 as it is the denomanot number of 7/2.Therefore,the denomanator will be canceled out with 2 and the number of 7/2 will become 7.
Steps by Steps solution:
C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O
=2×(C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O)
=2C3H8+7O2→6CO+8H2OC3H8+144O2→6CO+8H2O
6 0
3 years ago
A waterbed mattress has the following dimensions: 210 cm X 160 cm X 25 cm. The density of water is 62.4lb/ft3. What is the weigh
artcher [175]

<u>Answer:</u> The weight of water bed in pounds is 1850.16 lb

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 210 cm

b = breadth of cuboid = 160 cm

h = height of cuboid = 25 cm

Putting values in above equation, we get:

V=210\times 160\times 25=8.4\times 10^5cm^3=29.65ft^3      (Conversion factor:  1cm^3=3.53\times 10^{-5}ft^3 )

To calculate the mass of waterbed, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of waterbed = 62.4lb/ft^3

Volume of waterbed = 29.65ft^3

Putting values in above equation, we get:

62.4lb/ft^3=\frac{\text{Mass of waterbed}}{29.65ft^3}\\\\\text{Mass of waterbed}=(62.4lb/ft^3\times 29.65ft^3)=1850.16lb

Hence, the weight of water bed in pounds is 1850.16 lb

7 0
4 years ago
A 0.800 g sample of cuso4 (s was placed in calorimeter with 43.0g of water at an initial temp of 18.3 degrees celcious. as the c
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Hello it's 92479x027430=3057292
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