Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
45.6 mL of 0.0600 M of
is added to 25.0 mL of HCl of unknown concentration then , the concentration of HCl is 0.032 M .
Calculation ,
Formula used :
=
...( 1 )
Where
= concentration of
= 0.0600 M ( given )
= concentration of HCl = ? ( to be find )
= volume of
= 25.0 mL ( given )
= volume of HCl = 45.6 mL ( given )
Now , put the value of all volume and concentration in equation ( 1 ) we get .
0.0600 M × 25.0 mL =
× 45.6 mL
= 0.0600 M × 25.0 mL / 45.6 mL = 0.032 M
Therefore , concentration of unknown concentration of HCl is 0.032 M .
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You can Multiply the whole equation with 2 as it is the denomanot number of 7/2.Therefore,the denomanator will be canceled out with 2 and the number of 7/2 will become 7.
Steps by Steps solution:
C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O
=2×(C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O)
=2C3H8+7O2→6CO+8H2OC3H8+144O2→6CO+8H2O
<u>Answer:</u> The weight of water bed in pounds is 1850.16 lb
<u>Explanation:</u>
To calculate the volume of cuboid, we use the equation:

where,
V = volume of cuboid
l = length of cuboid = 210 cm
b = breadth of cuboid = 160 cm
h = height of cuboid = 25 cm
Putting values in above equation, we get:
(Conversion factor:
)
To calculate the mass of waterbed, we use the equation:

Density of waterbed = 
Volume of waterbed =
Putting values in above equation, we get:

Hence, the weight of water bed in pounds is 1850.16 lb