Answer:
The specific heat of iron is 0.45 J/g.°C
Explanation:
The amount of heat absorbed by the metal is given by:
heat = m x Sh x ΔT
From the data, we have:
heat = 180.8 J
mass = m = 22.44 g
ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C
Thus, we calculate the specific heat of iron (Sh) as follows:
Sh = heat/(m x ΔT) = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C
Answer:
V = 27.98 L
Explanation:
Given data:
Mass of CO₂ = 33.0 g
Pressure = 500 torr
Temperature = 27°C
Volume occupied = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 33.0 g/ 44 g/mol
Number of moles = 0.75 mol
Volume of CO₂:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
Now we will convert the temperature.
27+273 = 300 K
Pressure = 500 /760 = 0.66 atm
By putting values,
0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K × 300 K
V = 18.47 atm.L/0.66 atm
V = 27.98 L
10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.
What ois Theoretical yield ?
The quantity of a product obtained from a reaction is expressed in terms of the yield of the reaction.
The amount of product predicted by stoichiometry is called the theoretical yield, whereas the amount obtained actually is called the actual yield.
- As 2 moles (111.68 g) of Fe consumes 213 gm of Cl₂ to produce 2FeCl₃
Therefore ,
10 gm of Fe will consumes = 213 / 111.68 x 10 = 19 gm Cl₂
- As 2 moles (111.68 g) of Fe produces 2 mole (324 gm) of FeCl₃
Therefore ,
10 gm of Fe will produces = 324 / 111.68 x 10 = 29 gm FeCl₃
Hence , 10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.
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Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is
KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
