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3 years ago

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A 0.800 g sample of cuso4 (s was placed in calorimeter with 43.0g of water at an initial temp of 18.3 degrees celcious. as the c

uso(s dissolves in water, the temp increases to 20.2 degrees celcious. what value of /\h can be determined.

1 answer:

Serhud [2]3 years ago

6 0

Hello it's 92479x027430=3057292

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To solve this problem, we must mention Henry's law.

<em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>

It can be expressed as: C = KP,

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$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

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Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

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3 years ago