Question

45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?

Answer 1

45.6 mL of 0.0600 M of $Ba(OH)_{2}$ is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : $M_{1} V_{1}$ =  $M_{2} V_{2}$                 ...( 1 )

Where  $M_{1}$= concentration of $Ba(OH)_{2}$  =  0.0600 M ( given )

$M_{2}$ = concentration of HCl = ? ( to be find )

 $V_{1}$= volume of $Ba(OH)_{2}$  = 25.0 mL  ( given )

$V_{2}$ = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  $M_{2}$  × 45.6 mL

$M_{2}$  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

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