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fenix001 [56]
3 years ago
10

Which of the following are acceptable ways to make one liter of 1 M NaCl?

Chemistry
1 answer:
RSB [31]3 years ago
7 0

Initially, weigh the correct amount of NaCl calculated from the formula.

Number of moles  =\frac{Given mass in g}{Molar mass}

As 1 mole of NaCl is given and molar mass of NaCl is 58.44 g/mol, then

1 mole of NaCl= \frac{Given mass in g}{58.44 g/mol}

Mass of NaCl in g = {58.44 g}

Thus,

1 mole of NaCl = 58.44 g.

Now, the weighed amount of NaCl i.e. 58.44 g is added to a 1 liter container and then add small amount of water in the container to dissolve the salt. After that, fill the container with distilled water to the graduation mark or until the total volume reaches 1 liter.

Thus, option (c) is correct i.e. first put one mole of salt in the container then add the water with stirring till the total volume reaches 1 liter.


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4 0
3 years ago
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A student wishes to prepare 2.00 Liters of a 0.100 M KIO3 (molecular weight 214). The proper procedure is to weigh out:_____
Vsevolod [243]

Answer:

B

Explanation:

A. Wrong

The volume of water in 2kg of water might not be 2L

D is correct.

Firstly, we need to know that the number of moles equals the mass over the molar mass. Doing this with the particular data in tie question would give 0.2M.

Hence it is essential that what we get is 0.2M in one liter. But since we are gunning for 2L, adding more than one liter of water would affect the molarity, that is why it now will be 0.1M in 2L

C is wrong

What is prepared here is 0.05M in 2L

B is wrong

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E is wrong

5 0
4 years ago
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How many molecules in each sample?<br><br> 64.7 g N2<br> 83 g CCl4<br> 19 g C6H12O6
lilavasa [31]

Answer:

  • 1.39x10²⁴ molecules N₂
  • .25x10²³ molecules CCl₄
  • 6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:

  • 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
  • 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
  • 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:

  • 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
  • 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
  • 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
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No, since the slopes are different.
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Option C, slopes are same but y intercepts are different is the correct answer

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