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MakcuM [25]
3 years ago
13

A manufacturer makes three types of screws. Type A comes in a bulk pack of 1000 screws. Type B comes in a bulk pack of 500 screw

s. Type C comes in a bulk pack of 800 screws. Type A screws each have a probability of .001 of having a flaw. The probability is .003 for Type B and .005 for Type C.
(a) If a contractor buys one pack of each type of screws, find the expected total number of defective screws among the three packs.
(b) Find the probability that there are no more than 5 defective screws total among the three packs.
(c) Find the expected number of packs that have no more than 5 defective screws. (Your answer will be between 0 and 3.)
Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that a manufacturer makes three types of screws

Type             A        B           C Total

   

Pack         1000 500   800  

P for flaw 0.001 0.03 0.005  

Pack*p                 1 15                    4     20

a) Expected total number of defective screws = 20

b) For one pack each no of defective screws =20

Hence for 5 expected number number of packs form each should be 1/3

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To find the miles for 3rd day, we take away the miles she biked for the first two day from the total.

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Answer: She traveled 13 23/56 miles on the third day.
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