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PilotLPTM [1.2K]
3 years ago
13

12. Write the equation of a parabola with vertex at (2, -3) and focus at (2,5),

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Step-by-step explanation:

The basic form of equation:

(x-h)²=4a(y-k),

(h,k)=coordinates of vertex

(h, k+a) = coordinate of focus

For given parabola:

axis of symmetry: x=2

(h, k) =(2,-3)

(h, k+a)=(2,5)

k+a=5

-3+a=5

a=8(distance from vertex to focus on the axis of symmetry)

equation: (x-2)²=4×8(y+3)

(x-2)²= 32(y+3)

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Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the G.C.F. of 8x-6.

\triangle~\fbox{\bf{KEY:}}

  • G.C.F. stands for Greatest Common Factor.

So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:

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So the GCF is:

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Now, we can also factor it out by placing it outside the parentheses ():

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See, we factored it out by dividing both terms of the expression by the G.C.F.

\ddot\bigstar Remember this...

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Hope this helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students :)

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