Ask question

Ask question

All categories

3 years ago

10

Choose all of the conversions that are true. A. 24 ft = 2 in. B. 2 mi = 10,560 ft C. 12 mi = 2,640 ft D. 0.5 mi = 880 yd E. 0.5

ft = 3 in.
Will 5 star and thanks

1 answer:

Volgvan3 years ago

7 0

Answer:

B

C

Step-by-step explanation:

You might be interested in

Which statement is true about the graphs of the two lines and ? y= -8x -5/4 and y = 1/8x + 4/5

Ronch [10]

Y = -8x - 5/4......slope here is -8 or -8/1
y = 1/8x + 4/5...slope here is 1/8

what u have here are negative reciprocal slopes....negative reciprocal of a number can be found by flipping the number and changing the sign. So the negative reciprocal of -8/1 is 1/8 (see how I flipped the number and changed the sign)...and when u have negative reciprocal slopes, this means that ur lines are perpendicular.

7 0

2 years ago

What type of graph is made up of two or more overlapping circles?

trapecia [35]

The overlapping diagram you’re looking for is

B. Venn diagram.

5 0

3 years ago

Maria's fish tank has 17 liters of water in it. She plans to add 6 liters per minute until the tank has more than 47 liters. Wha

kondaur [170]

Answer:

t < 5

Step-by-step explanation:

47 > 6t + 17

30 > 6t

5 > t

t < 5

5 0

3 years ago

Hector collects golf balls at a driving range. each bucket holds 39 golf balls. if hector has 43 buckets to fill, estimate how m

Alborosie

There are 1677 golf balls to fill all the buckets. Hope it help!

4 0

2 years ago

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago