C(1;2)
a = 1
b = 2
r = 4
(x-a)² + (y-b)² = r²
(x-1)² + (y-2)² = 4²
(x-1)² + (y-2)² = 16
Answer:
Step-by-step explanation:
To find the y-intercept: replace x with 0
to find the x-intercept: replace y with 0
x-int:
0 = 10x - 32
32 = 10x
x = 3.2
(3.2, 0)
y-int:
y = 10(0) - 32
y = -32
(0, -32)
Answer:
0.3907
Step-by-step explanation:
We are given that 36% of adults questioned reported that their health was excellent.
Probability of good health = 0.36
Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.
Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.
i.e. 
Formula :
p is the probability of success i.e. p = 0.36
q = probability of failure = 1- 0.36 = 0.64
n = 11
So, 



Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907
I’m geussing the answer would be A because an ordered pair of that is (2,8) but the only difference is it’s negative so A hope this helps