Dododkdldlldlflffosjdididkdkdkdkd
Answer:
5,6241
Step-by-step explanation:
I have no idea if this is correct but I hope it is. I hope this helps.
There are infinitely many ways to do this. One such way is to draw a very thin stretched out rectangle (say one that is very tall) and a square. Example: the rectangle is 100 by 2, while the square is 4 by 4.
Both the rectangle and the square have the same corresponding angle measures. All angles are 90 degrees.
However, the figures are not similar. You cannot scale the rectangle to have it line up with the square. The proportions of the sides do not lead to the same ratio
100/4 = 25
2/4 = 0.5
so 100/4 = 2/4 is not a true equation. This numerically proves the figures are not similar.
side note: if you are working with triangles, then all you need are two pairs of congruent corresponding angles. If you have more than three sides for the polygon, then you'll need to confirm the sides are in proportion along with the angles being congruent as well.
Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation:
To solve this problem you need to know the law of cosines.
