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Masja [62]
3 years ago
14

Triangle LMN is similar to triangle PQR. The length of PQ is twice the length of LM.

Mathematics
2 answers:
Julli [10]3 years ago
4 0
The correct answer is letter c
dlinn [17]3 years ago
3 0

Answer:

C. \frac{9}{19}

Step-by-step explanation:

Since triangle LMN is similar to triangle PQR angle P and angle L are congruent.

If  \cos(L)=\frac{9}{19},then \cos(P)=\frac{9}{19}

The correct option is C.

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Is there a relationship between the different of the integers and the distance between them?
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Wait just a minute.  Hold up.  Hee haw. Whoa !

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Use slope-intercept form, y = mx + b to find the equation of the line that passes through the points (−6, 1) and (3, 4).
Mnenie [13.5K]

Answer:

y = one-third x + 3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step 1: Find slope <em>m</em>

m = (4 - 1)/(3 + 6)

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Step 3: Rewrite

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6 0
3 years ago
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There are muffins in a package.how many packages will be needed to feed 48people if each person has 2 muffins
Semmy [17]
You will need 94 muffins, but how many are in each package?
 
7 0
3 years ago
the first three steps of completing the square to solve the quadratic equation X2+4X-6=0 are shown below. what re the next 3 ste
Vilka [71]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The complete question is</em></u>

The first three steps of completing the square to solve the quadratic equation x2 +4x -6= 0, are shown below.

Step 1: x2 +4x= 6

Step 2: x2 +4x+4=6+4

Step 3: (x +2)^2=10

What are the next 3 steps?​

we have

step 4

Take square root both sides

\sqrt{(x+2)^2} =\sqrt{10}

step 5

Simplify

x+2=\pm\sqrt{10}

step 6

Solve for x

subtract 2 both sides

x=-2\pm\sqrt{10}

x_1=-2+\sqrt{10}

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3 0
3 years ago
Give an equation that goes through the line 3,-1 that is parallel to 6x-5
allochka39001 [22]
Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17

Hope this helps.
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