Question

JUU

Answer 1

Answer:

The solution set of given algebraic expression is  x = 7 and x = 3

Step-by-step explanation:

Given as :

The polynomial expression are

y = - x² + 6 x + 16                 ............1

y = - 4 x + 37                        ............2

Now, Solving these two equation

putting the value of y from eq 2 into eq 1

So, - x² + 6 x + 16 = - 4 x + 37

Or,  - x² + 6 x + 16 + 4 x - 37 = 0

Or, - x² + (6 + 4) x + (16 - 37) = 0

Or, - x² + 10 x - 21 = 0

Now, solving this quadratic equation by middle term break

i.e - x² + 7 x + 3 x - 21 = 0

Or, - x ( x - 7) + 3 ( x - 7) = 0

Or, (x - 7) ( - x + 3) = 0

Or, (x - 7) = 0  and ( - x + 3 ) = 0

∴ x = 7 , x = 3

So, The solution set of given algebraic expression is  x = 7 , x = 3

Hence, The solution set of given algebraic expression is  x = 7 and x = 3 Answer