Answer:
64π square feet (the formula for the area is r^2π so you have to multiply 8 with itself and you get 64. 64×π is 64π)
Answer:
78 inches.
Step-by-step explanation:
By definition, a foot is equal to 12 inches. That is modeled by the equation you wrote, y = 12x, where x is the amount of feet.
Substitute 6.5 for x. y = 12*6.5 = 78 inches.
I hope this helps!
Answer:
y -15 = -3(x +2)
Step-by-step explanation:
The slope will be ...
m = (y2 -y1)/(x2 -x1)
m = (-18 -15)/(9 -(-2)) = -33/11 = -3
Point-slope form is ...
y -y1 = m(x -x1) . . . . . line with slope m through point (x1, y1)
Using the first point, the equation is ...
y -15 = -3(x +2)
Answer:
![z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028](https://tex.z-dn.net/?f=%20z%20%3D%5Cfrac%7B33.3-%2034%7D%7B%5Cfrac%7B5%7D%7B%5Csqrt%7B54%7D%7D%7D%3D%20-1.028)
![z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441](https://tex.z-dn.net/?f=%20z%20%3D%5Cfrac%7B34.3-%2034%7D%7B%5Cfrac%7B5%7D%7B%5Csqrt%7B54%7D%7D%7D%3D%200.441)
An we can use the normal standard table and the following difference and we got this result:
![P(-1.028](https://tex.z-dn.net/?f=%20P%28-1.028%3Cz%3C0.441%29%3D%20P%28z%3C0.441%29%20-P%28z%3C-1.028%29%20%3D%200.670%20-0.152%20%3D0.518)
Step-by-step explanation:
Assuming this statement to complete the problem "with a standard deviation 5 mpg"
We have the following info given:
represent the mean
represent the deviation
We have a sample size of n = 54 and we want to find this probability:
![P(33.3 < \bar X< 34.3)](https://tex.z-dn.net/?f=%20P%2833.3%20%3C%20%5Cbar%20X%3C%2034.3%29)
And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:
![\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})](https://tex.z-dn.net/?f=%5Cbar%20X%20%5Csim%20N%28%5Cmu%20%2C%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%29)
And we can use the z score formula given by:
![z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=%20z%3D%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
And replacing we got:
![z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028](https://tex.z-dn.net/?f=%20z%20%3D%5Cfrac%7B33.3-%2034%7D%7B%5Cfrac%7B5%7D%7B%5Csqrt%7B54%7D%7D%7D%3D%20-1.028)
![z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441](https://tex.z-dn.net/?f=%20z%20%3D%5Cfrac%7B34.3-%2034%7D%7B%5Cfrac%7B5%7D%7B%5Csqrt%7B54%7D%7D%7D%3D%200.441)
An we can use the normal standard table and the following difference and we got this result:
![P(-1.028](https://tex.z-dn.net/?f=%20P%28-1.028%3Cz%3C0.441%29%3D%20P%28z%3C0.441%29%20-P%28z%3C-1.028%29%20%3D%200.670%20-0.152%20%3D0.518)