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Vikentia [17]
3 years ago
12

The base of a 13 foot ladder is 5 feet away from the wall. How far up the wall does the ladder reach? A)8 feet B)10 feet C)12 fe

et D)18

Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0

We can Notice from the Diagram that the Ladder with Wall Forms a Right Angled Triangle.

We know that In A Right Angles Triangle :

(Hypotenuse)² = (First Leg)² + (Second Leg)²

Here the Hypotenuse is the Length of Ladder and One of the Leg is Length away from the Wall

Substituting the Respective Values, We get :

⇒ 5² + (Second Leg)² = 13²

⇒ 25 + (Second Leg)² = 169

⇒ (Second Leg)² = 169 - 25

⇒ (Second Leg)² = 144

⇒ Second Leg = 12 Feet

⇒ The Ladder reaches a Height of 12 Feet

Option C is the Answer

Lisa [10]3 years ago
3 0

You are solving for the height. Use the formula:

c² - b² = a²      in which c = hypotenuse

(13)² - (5)² = a²

Simplify

169 - 25 = a²

144 = a²

Isolate the a. Root both sides

√144 = √a²

a = √144

a = √(12 x 12)

a = 12

C) 12 feet is your answer

~

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=

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2

2

+

6

+

4

=

0

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2x2+6x+4=0

=

2

a={\color{#c92786}{2}}

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⋅

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⋅

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brainliest and follow and thanks

8 0
2 years ago
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