Can anyone help me please?
2 answers:
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Answer:
Step-by-step explanation:
25 - 3x = -5(1 - x) - 2x
<u></u>
<u>We have to first get rid of the parenthesis:</u>
==> -5
==> 5x
<u>So now you should have:</u>
25 - 3x = -5 + 5x - 2x
<u>Combine like terms:</u>
25 - 3x = -5 + 5x - 2x
25 - 3x = -5 + 3x
<u>Add 3x to both sides:</u>
25 - 3x = -5 + 3x
+ 3x = + 3x
<u>And you should have:</u>
25 = -5 + 6x
<u></u>
<u>Add 5 to both sides:</u>
25 = -5 + 6x
+5 = +5
30 = 6x
<u>Divide 6 to both sides:</u>
=
5 = x
If p(x) and q(x) are arbitrary polynomials of degree at most 2 then
||p||||q|| = 26() and angle between p(x) and q(x) is 0.233.
Given that
<p,q> = p(-1)q(-1) + p(0) q(0) + p(3)q(3)
and p(x) = 2x²+ 6 , q(x)= 4x²-4x
then the values of p and q at x = -1,0,3 are given as;
x = -1,
p(-1) = 2(-1)² + 6 = 8 , q(-1) = 4(-1)² - 4(-1) = 8
x = 0,
p(0) = 2(0)² + 6 = 6 , q(0) = 4(0)² - 4(0) = 0
x = 3,
p(3) = 2(3)² + 6 = 24 , q(3) = 4(3)²- 4(3) = 24.
<p,q> = p(-1)q(-1) + p(0)q(0) + p(3)q(3)
= (8)(8) + (6)(0) + 24(24)
= 64 + 0 + 576
<p,q> = 640
Now we have to find ||p|| ||q||, for this we'll find ||p|| and ||q||
||p|| =
=
=
||p|| = 26
and
||q|| =
=
||q|| =
∴||p||||q|| = 26()
Now we have to find angle between p(x) and q(x),
∴ α = cos⁻¹
= cos ⁻¹
= cos ⁻¹
α = 13.34°
In radian
α = 0.233.
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