(a) without replacement:
P(S)=13/52=1/4
P(SS)=(1/4)*(12/51)=1/17
Probability of selecting two spades without replacement is 1/17.
(b) with replacement
P(S)=13/52=1/4
P(SS)=(1/4)(13/52)=1/16
Probability of selecting two spades with replacement is 1/16.
Answer:
it is definitely negative, i think it is -3/2
Step-by-step explanation:
is there a better picture of the graph?
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
</span><span>
</span>
1,10 and 2,5,
those are the pairs
