The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3
Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
Evaluated with x means that</span> x = 3.
f(3) = 3² + 2 * 3 = 9 + 6 = 15
15 ≠ 3, so, this is not correct.
2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
Evaluated with -3 means that x = -3.
(f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18
18 ≠ 3, so, this is not correct.
3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span> Evaluated with -3 means that x = -3.
f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
3 = 3, so this is correct.
4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
Evaluated with 3 means that x = 3.
f(3) = (3)² - 3 * 3 = 9 - 9 = 0
0 ≠ 3, so this is not correct.
1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer: -6 is the answer
Step-by-step explanation:
<h2>ADC is another way to name it.</h2><h2 /><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
1.C
2. A
Step-by-step explanation:
