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Answer:
The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of .
For this problem, we have that:
In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that and
.
Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).
Answer:
a) hydrostatic pressure at bottom = 10054.375 lb/ft-s2
b) hydrostatic force at bottom = 150815.625 lb-ft/s2
c) hydrostatic force at one end of aquarium = o
Step-by-step explanation:
Detailed explanation and calculation is shown in the image below
