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storchak [24]
3 years ago
8

PLEASE HELP ME WITH THIS THX!!!!!I REALLY NEED HELP WITH THIS!

Mathematics
2 answers:
Daniel [21]3 years ago
7 0
1. first point is x int., when y=0
x-4*0=-18, x=-18
(-18,0)
2. second point, y int, when x=0
0-4y=-18
-4y=-18
y=-18/-4=4.5
(0,4.5)
3. you can choose y=1, then x-4=-18, x=-14 , (-14,1)
or for this graph is
maybe better y=4, x-4*4=-18, x=-2  (-2,4)
x-4y=-18, y=3, x=-6 (-6,3)
UkoKoshka [18]3 years ago
4 0
I just want to reccomend desmos, it really helped me with graphing because im not so good at it

But what I got is: 
x-4y=-18
x=-18+4y

Root(-18,0)
Y-intercept: (0, 9/2)
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Let f and g be the functions defined by f(x) = 10^ (x+2 / 3) and g(x) = log (x3 / 100) for all positive real numbers,
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Answer:

F(x) and g(x) are not inverse functions.

Step-by-step explanation:

In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.

As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.

[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x[/tex]

Now we change the variables.

F(x)=log x-\frac{2}{3}

F(x) and g(x) are not inverse functions.

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