Ok ,try putting in 4.15 x 10<span>^-6</span>
OK im answering ............................................................................................................
Answer:
+73 yards.
Step-by-step explanation:
Since we have the first two quarters, we can simply work out the yardage for each game and add them together to get the total.
42-9 = 33 (first game)
58-18 = 40 (second game)
Therefore his total yardage was +73.
The first statement is true because 10 x 50 = 500
Answer:
Expected value would be $ 0.896
Step-by-step explanation:
Given,
The price of the lottery ticket = $44800000,
Also, the probability of winning the grand prize = .000000020,
Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket
= 44800000 × .000000020
= $0.896
Note : value of lottery ticket = prize amount - cost of each ticket,
Here the cost price of a ticket is not given,
That's why we did not consider it.
