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Ahat [919]
3 years ago
5

Help me this is due in 10 minutes

Mathematics
2 answers:
Nina [5.8K]3 years ago
6 0

i am pretty sure the answer is 8.

Neporo4naja [7]3 years ago
3 0

answer is

8 is the a

Step-by-step explanation:

12-8=4

4 is equal to 4

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Find b and then solve the equation: 2x^2+bx−10=0, if one of its roots is 5
slavikrds [6]

Vietas formula tells us that the product of our two roots is equal to the constant term of a quadratic over the leading coefficient, so:

[tex] r_1r_2=-\frac{-10}{2} \implies 5*r_1=-5 \implies r_1=-1[\tex]

It also tells us that the b term in our quadratic is equal to the negative of the sum of the terms divided by the leading coefficient, so:

[tex] r_1+r_2=-\frac{b}{2} \implies 4=-\frac{b}{2} \implies b=-8 [\tex]

So, one of our roots is 5, the other is -1, and our b value is 8.

4 0
3 years ago
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Which choice explains the correct way to move the decimal to find the quotient in the problem 31.28 ÷ 100? A. 2 places to the ri
aivan3 [116]
C. 2 places to the left

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7 0
3 years ago
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faust18 [17]
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3 0
4 years ago
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Please HELP !! ( already started it please help me finish it)​
FromTheMoon [43]

Answer:

Step-by-step explanation:

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6 0
4 years ago
Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

5 0
3 years ago
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